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3.5x^2-1000=0
a = 3.5; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·3.5·(-1000)
Δ = 14000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14000}=\sqrt{400*35}=\sqrt{400}*\sqrt{35}=20\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{35}}{2*3.5}=\frac{0-20\sqrt{35}}{7} =-\frac{20\sqrt{35}}{7} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{35}}{2*3.5}=\frac{0+20\sqrt{35}}{7} =\frac{20\sqrt{35}}{7} $
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